Help on Chemistry homework! How to calculate pH given pKb1 and pKb2

Help on Chemistry homework! How to calculate pH given pKb1 and pKb2




I'm so confused >.<



Here is the question:



Quinine (C20H24N2O2) is the most important alkaloid derived from cinchona bark. It is used as an antimalarial drug. For quinine pKb1 = 5.1 and pKb2 = 9.7 (pKb = ?log Kb). Only 1.0 g of quinine will dissolve in 1900.0 mL of water. Calculate the pH of saturated aqueous solution of quinine. Consider only the following reaction Q + H2O equilibrium reaction arrow QH + + OH ? described by pKb1, where Q = quinine.



Any help would be greatly appreciated!!





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