Statistics question: anova

Posted on 2013-11-27 14:03:00 in Statistics by JAYDYN

The population size of the survey was conducted with a total of 150 students. The amount of students infected versus non-infected was analyzed using the comparison of proportion theory.

The population proportion for positive individuals is not equal to that for non-infected individuals.

P1=proportion of individuals affected.

P2=proportion of individuals not infected

H_o: ?p??_1? ?p??_2

H_a: ?p??_1< ?p??_2

P-value = 88/150 = 0.586 Infected

P-value = 62/150 = 0.413 Non-infected



P= (15 0)/300= 0.5

Z= ?p??_1- ?p??_2 = 0.586-.413 = 0.173 = 1.90

? ?p??_c (1- ?p??_c) (1/n_1 +1/n_2 ) ?0.5(0.5)( 1/150 +1/150 ) = 0 .091



Comparison Proportion Equation

(?p??_1-?p??_2) ± z*? (?p??_1 (1-?p??_1))/n_1 + (?p??_2 (1-?p??_2)/n_2 )







Infected with Chlamydia Females 54 Males 34

Not Infected with Chlamydia Females 35 Males 27

total Females 89 Males 61

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