Chemistry Help!?

Posted on 2015-09-08 05:43:00 in Chemistry by JOE

Assume that dry air is 77.0% nitrogen and 23.0% oxygen by mass, and the pressure in the room remains constant at 1.000 atm. Dry Air- 0% humidity, Wet Air- 100% humidity.

1). "Percent humidity" is the ratio of the actual partial pressure of water in the air to the equilibrium vapor pressure of water at that temperature. Calculate the partial pressures of all three gases in "wet" air at 75*F and 90*F. Remember. the total pressure in the bathroom remains at 1.00atm, and the ratio of nitrogen gas and oxygen gas stays the same.

2). Calculate the mole fractions of all three gases in "wet" air at 75*F and at 90*F.

3). Calculate the density of "wet" air at 75*F and at 90*F.

---

Answer Comment

No Answers Posted Yet.