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Posted on 2015-09-21 06:42:00 in Physics by BOB

Consider a parallel plate capacitor with plate dimensions of 10 cm x 10 cm and a gap spacing of 2.00 cm. The capacitor is connected to a battery supplying a voltage across the capacitor of 2.00 kV. After the capacitor is fully charged, the battery is disconnected. A dielectric material is then inserted into the vacuum space to completely fill the capacitor. This result in a decrease of the capacitor voltage to 1.00 kV.

1. Find the vacuum capacitance.

2. Find the magnitude of the charge on each plate.

3. Find the capacitance after the dielectric is inserted.

4. Find the dielectric constant of the dielectric material.

5. Find the permitivity of the dielectric material.

6. Find the magnitude of the induced charge on each face of the dielectric material facing the capcitor plates.

7.Find the vacuum electric field between the plates

8.Find the electric field after the dielectric material is inserted.

9. Find the potential energy stored in the vacuum capacitor.

10. Find the potential energy stored in the capacitor after te dielectric material is inserted.

11. Discuss the motion of the dielectric material when it is inserted into the material capactitor.

12. What is the capactiance if the slab is only inserted half-way into the capactitor

13. What is the capacitance if the thickness of the slab is half of the gap spacing (but otherwise fully inserted into the capacitor)

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