What is the correct answer and why is it not C?

Posted on 2015-09-29 06:27:00 in Chemistry by KRISTY

Andrew placed the same amount of water into 2 equally sized beakers. He placed 1 mole of PbCl2 into Beaker X. He then placed 1 mole of Na2SO4 into Beaker Y.
Andrew then inserted electrodes attached to a light bulb circuit into each of the beakers.
The light bulb lit up faintly in Beaker X.
However, the light bulb lit up brightly in Beaker Y.
What conclusion can Andrew make about the electrolytic nature of PbCl2 & Na2SO4?

A. PbCl2 dissolves readily, whereas Na2SO4 goes into solution with difficulty.
B. Na2SO4 tends to precipitate out of solution, leaving only a few ions in solution.
C. When compared to water, Na2SO4 is a weak electrolyte in solution.
D. When PbCl2 is placed in water, it does not produce many free ions in solution.
E. Because PbCl2 is a molecule compound, it does not allow current to flow.

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