Can someone double check my work finding the derivative and instantaneous rate of change?

Posted on 2015-10-05 06:39:00 in Math by MATH CHECK

So this is the problem: The ebola virus is going through a small village. The number of people infected after t days is given by n (t)= 903/(1+300e-.7t). A. Find the derivate of the function (I got (1.896300×105 ×e-7t×ln(e))÷(1+300e-.7t) ...? can someone double check this?) B.find the rate at which the virus is spreading after 3 days. Namely the instantaneous rate of change after 3 days (so I just plugged 3 into the original equation and got 23.928 or 24 people, is this right?) C. Find the rate at which it is spreading after 10 days (so I plugged 10 into the original equation and got 709.03) D. Plot the derivative of the function, interpret what it means (so I got a very steep down sloping line, I and have no clue what that means....help??) This problem almost seems too easy, which means I probably did it wrong...help me please!

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