Help with this algebra 2 problem???

Posted on 2015-11-12 12:17:00 in Math by ROBET

(8x^2 - 328)/(x-6) - 40/(6-x)

What you're supposed to do is factor out -1 from the denominator (6-x) to make the right side of the equation + 40/(x-6), making the denominators equal so you can subtract. You're left with 8(x+6) as the final answer.

The thing is though, when I instead tried to factor out -1 from the left side of the equation instead of the right to make the denominators equal, I'm getting a totally different answer. I don't know what I'm doing wrong. I think I'm doing something out of order. Can someone work the problem out, but with factoring out -1 from the left side's denominator this time instead of the right?

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