Caculate power supply two impedances in series?
Caculate power supply two impedances in series?
Hi,
I had a question about a problem that is stated in my textbook, namely:
¨Two impedances in series are connected to an alternating voltage source. The voltage across the first impedance is equal to 180sin(314t) V and the voltage of the second impedance is equal to 120sin(314t + π/3) V. Calculate the power supply; choose from the following answers:
A. 240sin(0.43) V;
B. 262sin(314t + 0.43) V;
C. 262sin(314 + 0.41) V;
D. 240sin(0.41) V.¨
Thank you!
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