Caculate power supply two impedances in series?

Posted on 2016-03-04 18:55:00 in Engineering by DONYA

Hi, 

I had a question about a problem that is stated in my textbook, namely: 

¨Two impedances in series are connected to an alternating voltage source. The voltage across the first impedance is equal to 180sin(314t) V and the voltage of the second impedance is equal to 120sin(314t + π/3) V. Calculate the power supply; choose from the following answers: 
A. 240sin(0.43) V; 
B. 262sin(314t + 0.43) V; 
C. 262sin(314 + 0.41) V; 
D. 240sin(0.41) V.¨ 

Thank you!

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