Chemistry Question - Thermochemistry?

Chemistry Question - Thermochemistry?



A 248-g piece of copper initially at 314 degrees Celsius is dropped into 390 mL of water initially at 22.6 degrees Celsius. Assuming that at transfer occurs between the copper and the water calculate the final temperature 

Okay I have the equation set up (.385j/g deg C)(248g)(Tfinal-314 deg C) = (4.184 j/g deg C)(390g)(Tfinal - 22.6 deg C) 

I know that the T finals equal each other, but I am having trouble understanding how to get there. Details are appreciated. Thanks so much!





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