Calculate the molarity of a CaCl2 solution.?

Posted on 2016-03-14 18:44:00 in Chemistry by SPPITER

By adding an excess of AgNO3 (aq) at 25.00 mL of CaCl2 (ac), 4.498 g de AgCl are produced according to the following reaction: 2 AgNO3 (aq) + CaCl2 (aq) ---> 2 AgCl (s) + Ca(NO3)2 (aq). 
Calculate the molarity of the CaCl2 solution. { AgCl: 143.5 g/mol } 

A. 0.3138 M 
B. 0.6269 M 
C. 1.254 M 
D. 1.595 M 
E. 2.508 M 

Thank you! This is for a practice review! 

---

Answer Comment

No Answers Posted Yet.