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A student reascts 4.00 g of aniline (MW=93.14 g/mole) with 5..40 mL of acetic anhydride (MW=102.07 g/mole, p=1.082 g/mL) which produces 4.23 g of acetanilide (MW= 135.18 g/mole) 

1) HOW MANY MOLES OF ANILINE ARE USED IN THE REACTION? 

2) WHAT MASS OF ACCETIC ANHYDRIDE IS USED IN THE REACTION? 

3)HOW MANY MOLES OF ACCETIC ANHYDRIDE ARE USED IN THE REACTION ?? 

Please HELP



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Posted Answers:

1) 
The balanced equation of the reaction : 
C₆Hâ‚…NHâ‚‚ + (CH₃CO)â‚‚O → C₆Hâ‚…NHCOCH₃ + CH₃COOH 
(aniline) + (acetic anhydride) → (acetanilide) + (acetic acid) 

Mole ratio aniline : acetanilide = 1 : 1 

No. of moles of acetanilide produced = (4.23 g) / (135.18 g/mol) = 0.0313 mol 
No. of moles of aniline reacted = No. of moles of acetanilide produced = 0.0313 mol