Pauling Scale Of Electronegativity
Pauling Scale Of Electronegativity Assignment Help | Pauling Scale Of Electronegativity Homework Help
Pauling’s Scale of Electronegativity
In 1932, Linus Pauling was the first to propose a scale of electronegativity. He based his scale on the difference ( ΔE ) between the measured energy of a bond A-B [E (A - B) ] and the energy expected for the purely covalent bond A - B[ E (A - B)cov ] That is :
__________________ ΔE = [E (A - B) ] - [ E (A - B)cov ]
According to him if the tow atom A and B have the same electronegativity values then the molecule AB in bonded by purely covalent bonds as in homonuclear molecules A2 or B2. Then , [ E (A - B)cov ] would be the mean of [E (A - A) ] and [E (B - B)] that is:
____________________ [ E (A - B)cov ] = 1 [E (A - A) ] + [E (B - B) ] (Arithmetical mean)
2
or __________________ [ E (A - B)cov ] = [E (A - A) ] - [E (B - B) ]1/2 (Geometrical mean)
Pauling used geometric mean for his caluclatation. Substituting , we get
___________________ ΔE = E (A - B) ] - [E (A - A) ] - [E (B - B) ]1/2
When molecule AB is purely covalent then E (A - B)] = [ E (A - B)cov ] and ΔE = 0
____________________ ΔE = E (A - B) ] - [ E (A - B)cov ] = 0
____________________ ΔE = E (A - B) ] - [E (A - A) ] . [E (B - B) ]1/2 = 0
However, if the two atoms A and B have different electronegativities, the bond A-B will no longer be purely covalent and the energy E (A - B) would be greater than the mean of E A - A and E B - B
That : ______________ E (A - B) ] > [E (A - A) ] . [E (B - B) ]1/2
In other words, ΔE would be greater than zero.
This excess bond energy ΔE, is called the ionic-covalent resonance energy and arises due to the resonance stabilization of sort:
___________________ A - B <==> A + B _____________ ( B more electronegative than A )
covalent ionic
For more help in Pauling’s Scale of Electronegativity click the button below to submit your homework assignment
__________________ ΔE = [E (A - B) ] - [ E (A - B)cov ]
According to him if the tow atom A and B have the same electronegativity values then the molecule AB in bonded by purely covalent bonds as in homonuclear molecules A2 or B2. Then , [ E (A - B)cov ] would be the mean of [E (A - A) ] and [E (B - B)] that is:
____________________ [ E (A - B)cov ] = 1 [E (A - A) ] + [E (B - B) ] (Arithmetical mean)
2
or __________________ [ E (A - B)cov ] = [E (A - A) ] - [E (B - B) ]1/2 (Geometrical mean)
Pauling used geometric mean for his caluclatation. Substituting , we get
___________________ ΔE = E (A - B) ] - [E (A - A) ] - [E (B - B) ]1/2
When molecule AB is purely covalent then E (A - B)] = [ E (A - B)cov ] and ΔE = 0
____________________ ΔE = E (A - B) ] - [ E (A - B)cov ] = 0
____________________ ΔE = E (A - B) ] - [E (A - A) ] . [E (B - B) ]1/2 = 0
However, if the two atoms A and B have different electronegativities, the bond A-B will no longer be purely covalent and the energy E (A - B) would be greater than the mean of E A - A and E B - B
That : ______________ E (A - B) ] > [E (A - A) ] . [E (B - B) ]1/2
In other words, ΔE would be greater than zero.
This excess bond energy ΔE, is called the ionic-covalent resonance energy and arises due to the resonance stabilization of sort:
___________________ A - B <==> A + B _____________ ( B more electronegative than A )
covalent ionic
For more help in Pauling’s Scale of Electronegativity click the button below to submit your homework assignment