Coulombs Theorem
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Coulomb’s Theorem
Consider a conducting surface of very small surface area δs having charge density of σ coulombs per unit of surface area
Total charge on small surface δs = σδs coulombs.
According to Gauss’s theorem the total flux, ψ radiating from the charge of σδs coulombs = σδs coulombs.
Since in conducting surface no flux can exist inside and whole of the flux comes outward normally.
Flux density at the surface = ψ = σδs = σ
S δs
Field intensity at any point close to the surface,
E = D = σ N/C
∈o∈r ∈o∈r
Hence according to Coulombs theorem, the electric intensity at a surface of a conducting dy, having a charge density f coulombs per unit of surface area σ where ∈o∈r = E the absolute permittivity of the
∈o∈r
medium surrounding the conductor.
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Total charge on small surface δs = σδs coulombs.
According to Gauss’s theorem the total flux, ψ radiating from the charge of σδs coulombs = σδs coulombs.
Since in conducting surface no flux can exist inside and whole of the flux comes outward normally.
Flux density at the surface = ψ = σδs = σ
S δs
Field intensity at any point close to the surface,
E = D = σ N/C
∈o∈r ∈o∈r
Hence according to Coulombs theorem, the electric intensity at a surface of a conducting dy, having a charge density f coulombs per unit of surface area σ where ∈o∈r = E the absolute permittivity of the
∈o∈r
medium surrounding the conductor.
For more help in Coulombs Theorem click the button below to submit your homework assignment