Field Due To A Long Straight Conductor
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Field Due To A Long Straight Conductor
Consider a small length δl of a conductor of radius a meters and having a charge of q coulombs per meter of its length.
Total charge over the length δl of the conductor = qδl
According to Gauss’s theorem
The total flux crossing the surface = charge enclosed by the surface
or Ψ = qδl
Surface area crossed by the flux = 2παδl
Flus density, D = Total flux crossing the surface = qδl = q
Surface area crossed by the flux 2παδl 2πα
Field intensity at distance of meters from the conductor is given by
E = D = q
∈o∈r 2πα∈o∈r
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Total charge over the length δl of the conductor = qδl
The total flux crossing the surface = charge enclosed by the surface
or Ψ = qδl
Surface area crossed by the flux = 2παδl
Flus density, D = Total flux crossing the surface = qδl = q
Surface area crossed by the flux 2παδl 2πα
Field intensity at distance of meters from the conductor is given by
E = D = q
∈o∈r 2πα∈o∈r
For more help in Field Due To A Long Straight Conductor click the button below to submit your homework assignment