According to this law in any network of wires carrying currents he algebraic sum of all currents, meeting at a point is zero, or the sum of incoming currents towards any point is equal to the sum of outgoing currents away from that point.


Let I₁, I₂, I₃, I₄, I₅ and I₆ be the currents meeting at junction point O, flowing in the directions of arrow beads marked on the,.

Taking incoming currents as + ve and outgoing currents as – ve according to Kirchhoff’s first law.

I₁+I₂+I₃+I₄+I₅+I₆ = 0
I₁+I₄+I₅+ = I₃+I₃+I₆

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