Flow Through Orifice
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Flow through Orifice
Orifice:
• Orifice is a small opening of any cross sections such as circular, triangular or rectangular on the side or at the bottom of a tank, through which a fluid is flowing.
• It is used to measure the discharge of liquid from a tank or reservoir.
Classification of Orifice:
(1) Depending upon size
(i) Small orifice (ii) Large orifice
(2) Depending upon shape
(i) Circular
(ii) Rectangular
(iii) Triangular
(iv) Square
(3) Depending upon the shape of upstream edge of orifice
(i) Sharp edge orifice (ii) Bell-mouthed orifice
(4) Depending upon nature of discharge
(i) Free discharge orifice
(ii) Drowned or sub-merged orifice
(a) Fully submerged orifice
(b) Partially submerged orifice
• Orifice is a small opening of any cross sections such as circular, triangular or rectangular on the side or at the bottom of a tank, through which a fluid is flowing.
• It is used to measure the discharge of liquid from a tank or reservoir.
Classification of Orifice:
(1) Depending upon size
(i) Small orifice (ii) Large orifice
(2) Depending upon shape
(i) Circular
(ii) Rectangular
(iii) Triangular
(iv) Square
(3) Depending upon the shape of upstream edge of orifice
(i) Sharp edge orifice (ii) Bell-mouthed orifice
(4) Depending upon nature of discharge
(i) Free discharge orifice
(ii) Drowned or sub-merged orifice
(a) Fully submerged orifice
(b) Partially submerged orifice
Flow through a Circular Orifice
Consider a tank fitted with a circular orifice is one of its sides.
Let H be the head of liquid above the center of the orifice.
Consider two points at inside the tank and at vena-contract respectively.
Let flow is steady and at a constant head H
Apply Bernoulli’s Equation
+ V12 / 2g + Z1 = P2 / γ + V22 / 2g + Z2
Pressure at (1) - (1) (P / γ = H)
Pressure (2) - (2) (P / γ) = 0 atmospheric pressure
Z1 = Z2
V1 is very small as compare to V2 as A1 > A2
V1 = 0 H -0 = 0- V2 / 2g
V22 = 2gh V2 = √2gh
This is theoretical velocity. Actual velocity is less than this value.
For more help in Flow through Orifice click the button below to submit your homework assignment
Let H be the head of liquid above the center of the orifice.
Consider two points at inside the tank and at vena-contract respectively.
Let flow is steady and at a constant head H
Apply Bernoulli’s Equation
+ V12 / 2g + Z1 = P2 / γ + V22 / 2g + Z2
Pressure at (1) - (1) (P / γ = H)
Pressure (2) - (2) (P / γ) = 0 atmospheric pressure
Z1 = Z2
V1 is very small as compare to V2 as A1 > A2
V1 = 0 H -0 = 0- V2 / 2g
V22 = 2gh V2 = √2gh
This is theoretical velocity. Actual velocity is less than this value.
For more help in Flow through Orifice click the button below to submit your homework assignment