Loss Of Energy Due To Sudden Contraction
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Loss of Energy due to Sudden Contraction
Consider two section 1-1 and 2-2 before and after the contraction for a horizontal pipe.
Let, V1 = velocity of flow at 1-1
A1 = cross-sectional area at 1-1
V2 = velocity of flow at 2-2
A2 = cross-sectional area at 2-2
Vc = velocity of flow at vena-contract
Ac = cross-sectional area at 3-3
hc = loss of head due sudden contraction.
The loss of head occurring between section 1 to section 3 is appreciable. The major loss occurs when the jet of liquid enlarges from section 3 to section 2 i.e. mainly due to enlargement between section 3 to section 2.
From Equation, head loss is given by,
hc = (Vc – V2)2 / 2g
= V22/2g [ Vc/V2 – 1]2
According to the continuity equation,
Ac Vc = A2 V2
Vc / V2 = A2/Ac
Vc / v2 = 1/Cc
Putting the value Vc/V2 in Equation
hc = V22 / 2g [1/Cc – 1]
If the value of Cc = 0.62 (Assume) then,
hc = V22 / 2g [1/0.62 -1]
hc = 0.375 V22 / 2g
If the value of Cc is not given, then
hc = 0.5 V22 / 2g
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Let, V1 = velocity of flow at 1-1
A1 = cross-sectional area at 1-1
V2 = velocity of flow at 2-2
A2 = cross-sectional area at 2-2
Vc = velocity of flow at vena-contract
Ac = cross-sectional area at 3-3
hc = loss of head due sudden contraction.
The loss of head occurring between section 1 to section 3 is appreciable. The major loss occurs when the jet of liquid enlarges from section 3 to section 2 i.e. mainly due to enlargement between section 3 to section 2.
From Equation, head loss is given by,
hc = (Vc – V2)2 / 2g
= V22/2g [ Vc/V2 – 1]2
According to the continuity equation,
Ac Vc = A2 V2
Vc / V2 = A2/Ac
Vc / v2 = 1/Cc
Putting the value Vc/V2 in Equation
hc = V22 / 2g [1/Cc – 1]
If the value of Cc = 0.62 (Assume) then,
hc = V22 / 2g [1/0.62 -1]
hc = 0.375 V22 / 2g
If the value of Cc is not given, then
hc = 0.5 V22 / 2g
For more help in Loss of Energy due to Sudden Contraction click the button below to submit your homework assignment