Reynolds Transport Theorem
Reynolds Transport Theorem Assignment Help | Reynolds Transport Theorem Homework Help
Reynolds Transport Theorem
Let ‘cv’ denotes its control volume.
The system occupies new position due to fluid motion at time t + ( ) as shown by dotted surface. Let G define the location of volume in the flow field. An extensive property N (dependent upon mass) is a function of intensive properties n (independent of mass) such that
N = ∫ n ρ dV = N ( G. t )
The rate of change of N system is given by
(dN / dt) = (DN / Dt) = Lim [N (G0 + δG, t + δt) - N (G0 t] / δt
Δt → 0
Where G0 and G0 + ( ) locate the volumes t and t + ( ) respectively.
Adding and subtracting N (G0 , t + t) in the term under the limit and rearranging them as following two terms.
Lim [N (G0 + δG, t + δt) - N (G0 .t] / δt = (∂N / ∂t) G0 = ∂ / ∂t ∫ n ρ dV
Δt → 0
Which means the local rate of change of N in the control volume and
N [N (G0 + δG, + δt) - N (G0 , t + t) = Nm = N1
Where N1 and N2 refers the value of N for regions 1 and II respectively, the region II being common to both positions.
Nm = ∫ n ρ ( dA u δt) = ∫ n ρ dt (UdA)
CDA
N1 = ∫ n ρ dt (UdA)
ABCD
Subtracting I from III
Nm - N1 = ∫ n ρ dt (UdA)
ABCD
Which reduces the second limit term to ∫ n ( ρUdA )
We get, DN / Dt = ∫ n (ρUdA) + ∂ / ∂t ∫ n ρ dv
cs cs
This is the Reynolds transport equation. it shown that the rate of change N (extensive property) for a system equals the sum f the efflux of N across the control surface and the rate of change of N within the control volume.
For more help in Reynolds Transport Theorem click the button below to submit your homework assignment