Second Order Total Differentials
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Second-Order Total Differentials
The second-order total differential of a function of two variables is defined and obtained from the first order differential. If z = f (x,y), the first-order total differential of z is
dz = fx dx + fy dy.
The second-order total differential of z, denoted by d2z, is given by d2z = d (dz). Thus
d2z =d (fx dx + fy dy)
= ∂/∂x (fx dx + fy dy) dx + ∂/∂y (fxdx + fy dy) dy
= [fxx dx + fx ∂/∂x (dx) + fyx dy + fy ∂/∂x (dy)] dx
+ [fxy dx + fx ∂/∂y (dx) + fyy dy + fy ∂/∂y (dy)] dy
However, dx and dy are considered as constants, so
∂/∂x (dx) = 0, ∂/∂x (dy) = 0, ∂/∂y (dx) = 0, ∂/∂y (dy) = 0
d2z = (fxxdx + fxy dy) dx + (fxy dx + fyy dy) dy
(assuming fxy = fyx)
= fxx (dx)2 + fxy dx dy + fxy dx dy + fyy (dy)2
= fxx (dx)2 + 2fxy dx dy + fyy (dy)2 .
Hence the second-order total differential of z is
d2 z = fxx (dx)2 + 2fxy dx dy + fyy (dy)2.
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dz = fx dx + fy dy.
The second-order total differential of z, denoted by d2z, is given by d2z = d (dz). Thus
d2z =d (fx dx + fy dy)
= ∂/∂x (fx dx + fy dy) dx + ∂/∂y (fxdx + fy dy) dy
= [fxx dx + fx ∂/∂x (dx) + fyx dy + fy ∂/∂x (dy)] dx
+ [fxy dx + fx ∂/∂y (dx) + fyy dy + fy ∂/∂y (dy)] dy
However, dx and dy are considered as constants, so
∂/∂x (dx) = 0, ∂/∂x (dy) = 0, ∂/∂y (dx) = 0, ∂/∂y (dy) = 0
d2z = (fxxdx + fxy dy) dx + (fxy dx + fyy dy) dy
(assuming fxy = fyx)
= fxx (dx)2 + fxy dx dy + fxy dx dy + fyy (dy)2
= fxx (dx)2 + 2fxy dx dy + fyy (dy)2 .
Hence the second-order total differential of z is
d2 z = fxx (dx)2 + 2fxy dx dy + fyy (dy)2.
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