Potential Due To An Uniformly
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Potential due to an uniformly charged non-conducting solid sphere
In a conducting sphere, the entire charge is distributed uniformly in its entire volume. Let R be the radius of the non – conducting sphere. Let q be the total charge on the sphere.Volume charge density = p = q / (4πR3 / 3)
(i) Potential at an External Point
Let P be a point distant r from the centre O of the sphere. Divided the sphere into a large number of concentric spherical shells carrying charges q1, q2, q3 ….Potential at P due to } = __1__ __q1__
the shell of charge q1}___4πε0 r
The potential V due to the whole sphere is equal to the sum of the potentials due to all the shells.
. : V = __1__ __q1__ + __1__ __q2__ + ….
___ 4πε0 _ r 4πε0 r
= __1__ (q1 + q2 + q3 + ……)
___ 4πε0r
But (q1 + q2 + q3 + ……) = q, the charge on the sphere.
. : V = __1__ __q__
_______4πε0 r
E = - dV / dr = - d (__1__ __q__) = __1__ __q__
___________dr 4πε0 r _____4πε0 r2
Thus the charged sphere behaves toward an external point as if its entire charge were concentrated at its centre.
(ii) Potential at an Internal Point
Let the point P be inside the sphere at a distance r from the centre O. If we draw a concentric sphere through P, the point P is external for the inner solid sphere is radius r, and internal radius r and external radius R.The charge on the inner solid sphere is 4π r3 p/ 3.
Potential at P due to} = __1__ 4/3πr3 p = r2p
the inner solid sphere}___4πε0___r_____3ε0
The potential at P due to the whole shell of internal radius r and external radius R is
V2 = ∫rR px dx = p (R2 – r2).
_________ε0 ____2ε0
The total potential at P is
V = V1 + V2 = r2P + p (R2 – r2) = p(3R2 – r2)
____________3ε0 ___2ε0________6ε0
But p = q / (4πR3 / 3)
V = __3q__ (3R2 – r2)
4πR3 6ε0
. : V = __1__ q (3R2 – r2)
4πε0 2R3
E = - dV / dr = - d [__1__ q (3R2 – r2)] = __1__ qr
_____________dr 4πε0 2R3 ___ 4πε0 R3
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